Excel – Find the nth Word in a String (or String variable)

Send Us a Sign! (Contact Us!)

NOTA (Italiano): il conteggio ed il riconoscimento dell'ennsima parola, indicata dal valore/parametro intero (Integer) passato alla funzione, è possibile grazie al riconoscimento ed alla presenza (nel corso del [gs parsing] testuale) di uno o più "spazi" (stringa, non NULL), condizione necessaria e sufficiente a definire due parole..."distinte".

The following [gs function] will find the nth word in a [gs string]:

Function Find_nth_word(Phrase As String, n As Integer) As String
Dim Current_Pos As Long
Dim Length_of_String As Integer
Dim Current_Word_No As Integer
Find_nth_word = ""
Current_Word_No = 1
'Remove Leading Spaces
Phrase = Trim(Phrase)
Length_of_String = Len(Phrase)
For Current_Pos = 1 To Length_of_String
    If (Current_Word_No = n) Then
        Find_nth_word = Find_nth_word & Mid(Phrase, Current_Pos, 1)
    End If

    If (Mid(Phrase, Current_Pos, 1) = " ") Then
     Current_Word_No = Current_Word_No + 1
    End If
Next Current_Pos
'Remove the rightmost space
Find_nth_word = Trim(Find_nth_word)
End Function

It needs two arguments – the phrase that is to be searched and the word number:

Find_nth_word(“Automateexcel ls the worlds favourite Excel site”,4)

Will return “world”.

A blank is returned if the number of words in the phrase is less than the word number specified.

So: Find_nth_word(“Automateexcel ls the worlds favourite Excel site”,12)

Will return blank as there are not 12 words in the phrase “Automateexcel ls the worlds favourite Excel site”.

SOURCE	LINK (Automateexcel.com)	LANGUAGE	ENGLISH

SOURCE

LINK (Automateexcel.com)

LANGUAGE

ENGLISH